b^2+12b+20=0

Solution for b^2+12b+20=0 equation:

Simplifying
b2 + 12b + 20 = 0

Reorder the terms:
20 + 12b + b2 = 0

Solving
20 + 12b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(10 + b)(2 + b) = 0

Subproblem 1
Set the factor '(10 + b)' equal to zero and attempt to solve:

Simplifying
10 + b = 0

Solving
10 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + b = 0 + -10

Combine like terms: 10 + -10 = 0
0 + b = 0 + -10
b = 0 + -10

Combine like terms: 0 + -10 = -10
b = -10

Simplifying
b = -10
Subproblem 2
Set the factor '(2 + b)' equal to zero and attempt to solve:

Simplifying
2 + b = 0

Solving
2 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + b = 0 + -2
b = 0 + -2

Combine like terms: 0 + -2 = -2
b = -2

Simplifying
b = -2
Solution
b = {-10, -2}